If '1' is one of the roots of
arº+3x+5=0 then the second
root is
Answers
Given : '1' is one of the roots of ax² + 3x + 5 = 0
To find : Second root
Solution:
ax² + 3x + 5 = 0
1 is the one of the roots
Hence a(1)² + 3(1) + 5 =0
=> a + 8 = 0
=> a= -8
-8x² + 3x + 5 = 0
=> -8x² + 8x - 5x + 5 = 0
=> -8x(x - 1) -5(x - 1) = 0
=> (-8x - 5)(x - 1) = 0
=> -8x - 5 = 0
=> x = -5/8
Another roots = - 5/8
Another method let say other root = y
Sum of roots 1 + y = - 3/a
Product of roots = 1*y = 5/a
=> a = 5/y
=> 1 + y = -3/(5 /y)
=> 1 + y = -3y/5
=> 5 + 5y = -3y
=> 8y = -5
=> y = -5/8
Other roots = - 5/8
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