Question

If 1 is one of the zeroes of polynomial p(x)=ax*x-bx+1 then

Answer 1

If 1 is one of the zeroes of polynomial p(x)=ax*x-bx+1 then

p(1)=a(1)×(1)-b(1)+1

= a×(1-b)+1

p(1)=a-ab+1= 0

Hope it helps you.