Question

If 1 is one of the zeroes of the polynomial p(x) = ax2 - bx + 1, then​

Answer 1

Step-by-step explanation:

$zero = 1 \\ \\ p(x) =a {x}^{2} - bx + 1 \\ \\ \\ p(1) = a( {1}^{2} ) - b(1) + 1 \\ \\ \\ = a - b + 1$

Hope that it will help you...Happy learning ♥️♥️♥️