Question

If 1 is one of the zeros of the polynomial 7x-x^3 -6 find the other two zero

Answer 1

$- {x}^{3} + 7x - 6 = 0 \\ {x}^{3} - 7x + 6 = 0 \\ {x}^{3 } - x - 6x + 6 = 0 \\ {x} ( {x}^{2} - 1) - 6(x - 1) = 0 \\ (x - 1)( {x}^{2} + x - 6) = 0 \\ (x - 1)( {x}^{2} + 3x - 2x - 6) = 0 \\ (x - 1)(x + 3)(x - 2) = 0 \\ so \: other \: two \: zeroes = - 3 \: and \: 2$