Question

If -1 is one of the zeros of the polynomial p(x) = 3x³ - 5x² - 11x - 3, find the other two zeros. [ Best answer will be brainliest ]

Answer 1

Since we know that -1 is a zero of $p(x) = 3x^{3} - 5x^{2} - 11x - 3$, 

$(x+1)$ is hence a factor of $p(x)$


Dividing p(x) by (x+1) we get: $\frac{3x^3-5x^2-11x-3}{x+1}:\quad 3x^2-8x-3$

Now factorising $3x^2-8x-3$ we get:

$(3 x + 1) (x - 3)$

Hence the remaining factors are $x = -\frac{1}{3}$ or $x = 3$

Answer 2

Hola Friend ✋✋✋

-1 is a factor ....

x = - 1

x + 1 is a factor of p(x)

Dividing p(x) by ( x + 1 )

Plz see attachment for the dividing process....

q(x) = 3x² - 8x - 3 = 0

by quadratic formula
$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x = \frac{8 + - \sqrt{64 + 36} }{6} \\ \\ x = \frac{8 + - 10}{6} \\ \\ x = 3 \: or \: - \frac{1}{3}$

Hope it helps