Question

if 1 is root of equations ay(sq) +ay + 3 =0 and y(sq) + y + b = 0 then ab equals to ?

Answer 1

1 is root of given equation ,
ay^2+ay+3=0
so,
a (1) +a (1) + 3=0
a=-3/2

also,

y^2+y+b=0

(1)^2+(1)+b=0
b= -2

now,
ab= (-3/2)(-2)=3 (ans )

Answer 2

The root of the equation satisfies the equation ;

ay^2 + ay + 3 = 0
a(1)^2 + a(1) + 3 = 0
2a = -3

a = -3/2

y^2+y+b = 0
(1)^2 + (1) + b = 0

b = -2
-------------------–---------------
ab
= (-3/2)×(-2)
= 3
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