Question

if -1 is the double root of the equation x-ax²-ax+1=0, then find the value of a​

Answer 1

Answer:

-1

Step-by-step explanation:

x-ax²-ax+1

-ax² -ax + x +1

-ax ( x + 1 ) + 1 (x + 1)

(x + 1)(-ax + 1 )

since - 1 is the double root

thus, .

-a×(-1) + 1 = 0

a + 1 = 0

a = -1

Answer 2

Answer:

the answer is (-1) ....