If 1 is the root of quadratic equation 2x^2-bx+6=0,then the value of b is
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2x^2 -bx + 6
2(1)^2 -b(1)+6 =0 { roots when put in equation always get 0}
2-b+6 =0
8-b = 0
b= 8
your answer is 8
2(1)^2 -b(1)+6 =0 { roots when put in equation always get 0}
2-b+6 =0
8-b = 0
b= 8
your answer is 8
MARKBUSTER:
but the given option is 4
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