if 1 is the zero of polynomial
then find the value of a
Answers
Answered by
1
Heya !!!
Given that 1 is the one zero of the given Polynomial.
P(X) = AX² - 3(A -1)X - 1
P(1) = A × (1)² - 3(A-1)×1 -1
=> A × 1 - 3A + 1 -1 = 0
=> A - 3A = 0
=> -2A = 0
=> A = 0/-2
=> A = 0
HOPE IT WILL HELP YOU..... :-)
Given that 1 is the one zero of the given Polynomial.
P(X) = AX² - 3(A -1)X - 1
P(1) = A × (1)² - 3(A-1)×1 -1
=> A × 1 - 3A + 1 -1 = 0
=> A - 3A = 0
=> -2A = 0
=> A = 0/-2
=> A = 0
HOPE IT WILL HELP YOU..... :-)
Answered by
6
Given that zero is 1,
So, x = 1
ax² -3(a - 1)x - 1 = 0
a(1)² - 3(a - 1)(1) - 1 = 0
a - 3a + 1 - 1 =0
-2a = 0
a = 0/2
a = 0
I hope this will help you
(-:
So, x = 1
ax² -3(a - 1)x - 1 = 0
a(1)² - 3(a - 1)(1) - 1 = 0
a - 3a + 1 - 1 =0
-2a = 0
a = 0/2
a = 0
I hope this will help you
(-:
Similar questions