Question

If -1 is thr zero of he polynomialp(x) equal o ax cube - xsquare+x+4.Find the value of a

Answer 1

Hii..

x=-1

ax^3-x^2+x+4=0

a*-1-1+(-1)+4=0

-a+4=0

a=4...

Answer 2

x=-1

p(x)=$a {x}^{3} - {x}^{2} + x + 4 = 0$

$a( { - 1})^{3} - ( { - 1})^{2} + ( - 1) + 4 = 0$

$- 1a - 1 - 1 + 4 = 0$

$- 1a - 2 + 4 = 0$

$- 1a + 2 = 0$

-1a=-2

$a = \frac{ - 2}{ - 1}$

a=-2

Hope it helps:)