Question

if 1 is zero of p(x)=ax^-3(a-1)-1 then find the value of a​

Answer 1

Answer:

Given: p(x)=ax

2

−3(a−1)x−1

One of the zero =1

As one of the zeroes is 1, substituting it in the polynomial

⇒p(1)=0=a−3(a−1)−1

⇒0=−2a+3−1

⇒a=1

Answer 2

Answer:

1

Step-by-step explanation:

p(x) = ax²- 3(a-1)x -1

Given, 1 is its zero

p(x) = a(1)² -3(a-1)1 -1 = 0

a - 3a+3 -1 = 0

-2a + 2 = 0

-2a = -2

a = -2/-2

a = 1

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