if 1 is zero of the polynomial p(x)=ax^2 -3( a-1)x-1,then the value of 'a' is
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Answer:
a = 1
Step-by-step explanation:
Place x = 1 in
==: ax^2 - 3 (a - 1) x - 1 = 0
==: a - 3 (a - 1) - 1 = 0
==: a - 3a + 3 - 1 = 0
==: -2a + 2 = 0
==: -2a = -2
==: a = 1
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