Question

If 1 is zero of the polynomial p(x) = ax2 - 3(a-1)x - 1, then the value of 'a' is

Answer 1

Answer: 1

Step-by-step explanation:

p(x) = ax²- 3(a-1)x -1

Given, 1 is its zero

p(x) = a(1)² -3(a-1)1 -1 = 0

a - 3a+3 -1 = 0

-2a + 2 = 0

-2a = -2

a = -2/-2

a = 1

Answer 2

Given:

If 1 is zero of the polynomial p(x) = ax2 - 3(a-1)x - 1

To Find:

Find the value of 'a'

Solution:

Zero of a polynomial is defined when that number is put in the P(x) replacing x then if it is equal to 0 then it is said to be the zero of the polynomial. when a different is obtained then it is said to be the remainder of that (x-a) where a is the number put in the P(x)

Here putting P(1) in the polynomial p(x) and equating it to 0 as it is the zero of the polynomial, we get an equation as,

$P(x)=ax^2-3(a-1)x-1\\P(1)=a*1-3(a-1)-1\\a-3a+3-1=0\\-2a=-2\\a=1$

So the value of a is 1  

Hence, the value of a is 1.