Question

if '1' isa zero of the polynomial p(x) = ax^3-x^2 +x + 4 then find the value of 'a'​

Answer 1

Answer:

4

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

p(x)=ax³-x²+x+4

since -1 is a zero of p(x)

p(1)=0

replace 1 with x in p(x)

a(1³)-(1²)+(1)+4=0

a-1+1+4=0

a+4=0

a=-4