Question

If ( 1/k , 6) lies on the equation 2x-3y=1 , then find the value of k.

Answer 1

Hey

Here is your answer,

if (1/k,6) lies on the equation 2x-3y=1 the x=1/k and y=6

substitute the values of x and y in the given equation,

2 ( 1/k ) - 3 x 6 = 1

2/k = 1+18

2/k = 19

k = 2/19

hope it helps you...

Answer 2

Let x=1/k and y=6

So,.


$2 \times \frac{1}{k} -( 3 \times 6) = 1 \\ \\ \frac{2}{k} - 18 = 1 \\ \\ \frac{2}{k} = 18 + 1 \\ \\ \frac{2}{k} = 19 \\ \\ k = \frac{2}{19}$


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