if 1 kg what is mixed with 2 kg of liquid of density 3 gram per centimetre cube then the average density of mixture will be?
Answers
Mass of water= 1kg = 1000g,
density of water =1g/cm3
So volume of water = 1000cm3
Mass of 2nd liquid=2kg= 2000g
Density of second liquid=2g/cm3
So volume=2000/3 cm3
Total Mass = 1000+2000=3000g
and total volume= 1000 + 2000/3 = 5000/3 cm3
So avg density = Mass / volume = 3000/5000/3 = 1.8gm/cm3
The average density of mixture is 0.0015 kg/m³
Explanation:
The average density is given by the formula:
Average density = (Total mass)/(Total volume)
Mass of water = 1 kg
Mass of another liquid = 2 kg
⇒ Total mass = Mass of one liquid + Mass of another liquid
∴ Total mass = 1 kg + 2 kg = 3 kg
Density of water = 1000 kg/m³
Volume of water = (Density of water)/(Mass of water)
∴ Volume of water = 1000/2 = 500 kg
Now,
Density of another liquid = 3 g/cm³ = 3000 kg/m³
Volume of another liquid = (Density of the liquid)/(Mass of liquid)
∴ Volume of another liquid = 3000/2 = 1500 kg
Total volume = Volume of water + Volume of another liquid
∴ Total volume = 500 + 1500 = 2000 kg
Now,
∴ Average density = 3/2000 = 0.0015 kg/m³