If 1, log, x, log, y,-15 log, z are in A.P., then
(a) 2) = x
(b)x=y-1
(c) 2-3 = y
(d) all of these
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Step-by-step explanation:
Given 1, logy x, logz y, -15 logx z are in A. P.
Let the common difference be d.
logy x – 1 = d
logy x = 1+d
x = y1+d …(i)
logz y = 1+2d
y = z1+2d …(ii)
-15 logx z = 1+3d
z = x-(1+3d)/15 …(iii)
x = y1+d = z(1+2d)(1+d) = x-(1+d)(1+2d)(1+3d)/15
Comparing powers of x
(1+d)(1+2d)(1+3d) = -15
(2d2+3d+1)(3d+1) = -15
6d3+11d2+6d+16 = 0
(d+2)(6d2-d+8) = 0
=> d = -2
Therefore, x=z^3
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