Question

If 1, log81(3x+48) and log9(3x−83) are in A.P., then x is equal to please fast its urgent

Answer 1

Answer:

33.125 (exact value not approx)

Step-by-step explanation:

we know when numbers a,b,c are in A.P. , they are written in the form a+c=2b.

hence this can be written as 1+ log9(3x-83) = 2log81(3x+48)

bringing all terms in form of log9 we get,

log9(9) + log9(3x-83)=2log(9^2)(3x+48)

log9(27x-747)= 2log(9^2)(3x+48) (loga+logb=log(ab))

log9(27x-747)= 2*(1/2)*log9(3x+48)

(log(a^2)(b)= (1/2)*loga(b))

log9(27x-747)=log9(3x+48)

removing log on both sides,

27x-747=3x+48

Solving for x we get x=33.125

Putting this value in the equation, we notice log value isn't negative.

Therefore x=33.125 is the correct answer

Answer 2

x is equal to 9. taking 2 times tge middle is equal to sum of first and third term..