Question

If 1 mg of U²³⁵ is completely annihilated, the energy liberated
is
(a) 9 × 10¹⁰ J (b) 9 × 10¹⁹ J
(c) 9 × 10¹⁸ J (d) 9 × 10¹⁷ J

Answer 1

Answer:

hey mate here is your answer.

If 1 mg of U²³⁵ is completely annihilated, the energy liberated - 9 x 10¹⁰

I hope it's helpful for you

Answer 2

To find:-

The Energy liberated when 1 milli gram of “U” is completely annihilated = ?

Formula:-

Einstein mass-energy relationship,

$energy = \frac{mass}{ {speed \: of \: light}^{2} }$

Solution:-

Given,

mass = 1 milli gram

$= > mass = 1 \times {10}^{ - 6} kg$

we have known that, speed of light (c)

$= 3 \times {10}^{8} \frac{m}{s}$

So, Energy liberated:-

$= (1 \times {10}^{ - 6} ) \times (3 \times {10}^{8}</u></strong><strong><u>)</u></strong><strong><u> \\ = 9 \times {10}^{10} joule$

Hence, Option (a) is the Correct answer.

Hope it helps to you.