Question

If 1 mL of water is introduced into a 1 L flask at
27°C, how many moles of water are in the
vapour phase when equilibrium is established?
Vapour pressure of water at 300 K is 0.032 bar
R = 0.083 bar Lk-1 mol-1
4.4 x 10-2 mol
5.6 x 10-3 mol
1.27 x 10-3 mol
1.54 x 10-3 mol

plz solve this
​

Answer 1

Answer:

PT=200 mm Hg

PH2O=93 mm Hg

P1=200 mmHg−93 mmHg=107 mmHg

We know, PV=K at constant T.

P1V1=P2V2

107×1=P2×2

P2=53.5 mm Hg

Pmix=(53.5+93) mmHg =146.5 mm Hg