If 1 mL of water is introduced into a 1 L flask at
27°C, how many moles of water are in the
vapour phase when equilibrium is established?
Vapour pressure of water at 300 K is 0.032 bar
R = 0.083 bar Lk-1 mol-1
4.4 x 10-2 mol
5.6 x 10-3 mol
1.27 x 10-3 mol
1.54 x 10-3 mol
plz solve this
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Answer:
PT=200 mm Hg
PH2O=93 mm Hg
P1=200 mmHg−93 mmHg=107 mmHg
We know, PV=K at constant T.
P1V1=P2V2
107×1=P2×2
P2=53.5 mm Hg
Pmix=(53.5+93) mmHg =146.5 mm Hg
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