if 1 mole of nitrogen molecules weighs 28 g , calculate the mass of one molecule of nitrogen in grams........
Answers
Answered by
106
According to the Avogadro gas law, one mol of gas contains 6.022 *10^23 molecules under the standard temperature and pressure.
One mole of nitrogen contains 28 gram.
In short 28 grams contains 6.022*10^23 molecules, therefore mass of one molecule contains (28/6.022)*10^23 = 4.6*10^ (-23) g.
One mole of nitrogen contains 28 gram.
In short 28 grams contains 6.022*10^23 molecules, therefore mass of one molecule contains (28/6.022)*10^23 = 4.6*10^ (-23) g.
Answered by
74
mass of 6.022*1023molecules=28g
mass of one molecule=?
28/6.022*1023
=4.64*6.022*10^23g
=27.94208*10^23g
hope it helps to you.
mass of one molecule=?
28/6.022*1023
=4.64*6.022*10^23g
=27.94208*10^23g
hope it helps to you.
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