Question

If (-1)^n + (-1)^4n = 0, then n is​

Answer 1

Step-by-step explanation:

467 is the correct answer

Answer 2

Answer:

(−1)

(−1) n

(−1) n =−1 only when n is odd

(−1) n =−1 only when n is oddNow, 4n will always be an even integer because it is a multiple of 2 i.e. (2×2n).

(−1) n =−1 only when n is oddNow, 4n will always be an even integer because it is a multiple of 2 i.e. (2×2n).So (−1)

(−1) n =−1 only when n is oddNow, 4n will always be an even integer because it is a multiple of 2 i.e. (2×2n).So (−1) 4n

(−1) n =−1 only when n is oddNow, 4n will always be an even integer because it is a multiple of 2 i.e. (2×2n).So (−1) 4n will be equal to 1.

(−1) n =−1 only when n is oddNow, 4n will always be an even integer because it is a multiple of 2 i.e. (2×2n).So (−1) 4n will be equal to 1.If n is odd, equation will become −1+1=0

(−1) n =−1 only when n is oddNow, 4n will always be an even integer because it is a multiple of 2 i.e. (2×2n).So (−1) 4n will be equal to 1.If n is odd, equation will become −1+1=0So n has to be odd.