Question

If 1 newton tangential force is required to maintain the velocity gradient of 1ms^(-1)//m between two parallel layers of liquid each of area 1 sq m, the coefficient of viscosity of liquid is said to be…………

Answer 1

Answer:

ur answer is above given the

Explanation:

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Answer 2

Given:

• 1 newton tangential force is required to maintain the velocity gradient of 1 $ms^{-1}/m$
• two parallel layers of liquid each of area 1 sq. m.

To find: the coefficient of viscosity of the liquid is said to be ?

Explanation:

by question, we have the values,

                 F = 1N

                 $\frac{dv}{dz} = 1$

                  A = 1 $m^{2}$  

we know that newton's law of viscosity formula,

                  F = ηA$\frac{dv}{dz}$

                  η = $\frac{F}{A\frac{dv}{dz} }$

by putting the given values in the euqation,

                     = $\frac{1}{1}$

                  η = 1 pa. sec.

Hence the coefficient of viscosity of the liquid is said to be 1 pa. sec.