Question

if ✓1 of quadratic polynomial 2xsquare+3x+p is 3 . find the other root also .find the value of p

Answer 1

$2 {x}^{2} + 3x + p = 0 \\ 2 ({3})^{2} + 3(3) + p = 0 \\ 18 + 9 + p = 0 \\ p = - 27$
$2 {x}^{2} + 3x - 27 = 0 \\ \alpha + \beta = \frac{ - 3}{2} \\ 3 + \beta = \frac{ - 3}{2} \\ \beta = \frac{ - 3}{2} - 3 \\ \beta = \frac{ - 3 - 6}{2} \\ \beta = \frac{ - 9}{2}$
another root is -9/2