Math, asked by mohammedjawaad, 3 months ago

If 1 of the roots of x²-Kx+6=0 is 2 then find its other zeroes using quadratic formula. Whoever answers will be marked brainliest. U WILL GET 35​

Answers

Answered by XxHeartHeackerJiyaxX
1

Answer:

Since x=2 is a root of the equation

2x2+kx−6=0

2k+2=0

k=−1

Putting k =-1 in the given equation, we get,

2x2−x−6=0

(x−2)(2x+3)=0

x=2,−23

Hence, the other root is −23.

Answered by Anonymous
2

GIVEN

x = 2 is a root of the equation x² - Kx + 6 = 0

SOLUTION

x² + kx − 6 = 0

Putting x = 2, we get,

2² + 2k - 6 = 0

4 + 2k - 6 = 0

2k - 2 = 0

k = 1

➠‎ Putting k = 1 in the given equation, we get,

x² + 1 × x − 6 = 0

x² + x - 6 = 0

x² + 3x - 2x - 6 = 0

x(x + 3) - 2(x + 3) = 0

(x + 3)(x - 2) = 0

x = 2 or -3

➠‎ Hence, the other root is -3.

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