if 1 ohm, 2ohm, 3ohm resistors connected in parallel with a 6volts battery then what is potential difference at 1 ohm resistance, 2 ohm resistance and 3 ohm resistance.
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If two resistors of resistances 3 ohm and 2 ohm are connected in parallel to a 6 volt battery, then what is the total current in the circuit?
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For the above circuit the easiest way to find the total current from the battery is:
I(current R1)= E(voltage R1)/R1(3 ohm)= 6V/3 ohm= 2A (amps)
I(current R2)= E(voltage R2)/R2(2 ohm)= 6v/2 ohm= 3A (amps)
I(total current)= I(current R1) + I(current R2)= 2A + 3A= 5A
This is all done by Ohms Law: E=IR or I= E/R or R=E/I
The voltage in a parallel circuit is the same across all resisters and is the supply E
The total current of E(supply) is equal to the sum of the branches of current:
I(total)= I1 + I2 by Kirchhoff Current Law
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