if (1,p/3) is the mid point of the line segment joining the point (2,0) and (0,2/9), then show that the line 5x+3y+2=0 passes through the point (-1,3p)
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Hi ,
let ( x1 , y1 ) = A( 2 , 0 ) ,
( x2 , y2 ) = B ( 0 , 2/9 ) ;
mid point of joining of A and B = ( x1+ x2 /2 , y1 + y2 /2 )
( 1 , p/ 3 ) = ( 0 + 2 /2 , 0 + 2/9 / 2 )
= ( 1 , 1/9 )
p/3 = 1/9
[ ∵ If ( a , b ) = ( c , d ) then a = c and b = d ]
p = 1/3 --- ( 1 )
according to the problem given ,
put ( -1 , 3p ) in the equation 5x + 3y + 2 =0
5 ( -1 ) + 3 × ( 3p ) + 2 = 0
-5 + 3 × 3 ( 1/3 ) + 2 =0 [ from ( 1 ) ]
-5 + 3 + 2 =0
0 = 0 [ true ]
Therefore ,
5x + 3y + 2 =0 line passes through the
point ( -1 , 3p ) .
let ( x1 , y1 ) = A( 2 , 0 ) ,
( x2 , y2 ) = B ( 0 , 2/9 ) ;
mid point of joining of A and B = ( x1+ x2 /2 , y1 + y2 /2 )
( 1 , p/ 3 ) = ( 0 + 2 /2 , 0 + 2/9 / 2 )
= ( 1 , 1/9 )
p/3 = 1/9
[ ∵ If ( a , b ) = ( c , d ) then a = c and b = d ]
p = 1/3 --- ( 1 )
according to the problem given ,
put ( -1 , 3p ) in the equation 5x + 3y + 2 =0
5 ( -1 ) + 3 × ( 3p ) + 2 = 0
-5 + 3 × 3 ( 1/3 ) + 2 =0 [ from ( 1 ) ]
-5 + 3 + 2 =0
0 = 0 [ true ]
Therefore ,
5x + 3y + 2 =0 line passes through the
point ( -1 , 3p ) .
Answered by
1
Hope this may help u.......
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