Question

If (1 - p) is a root of quadratic equation x2 + px + (1 - p) = 0 then find its roots?

Answer 1

One root=1-p
Let the second root=x
so,Sum of zeroes
one root+second root = -b/a
1-p+x= -p/1
1-p+x= -p
x= -p+p-1
-p and +p get cancelled
x= -1
so,Second root of this quadratic equation -1
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Answer 2

Answer:

given the root is x=(1-p)

then (1-p)²+(1-p)p+(1-p)=0

(1-p)[1-p+p+1]=0

1-p=0

p=1

then equation becomes

x²+x=0

x(x+1)=0

then x=(0,-1)