Question

If (1 – p) is a root of quadratic equation x2 + px + (1 – p) = 0, then its roots are

0, -1
1, 1
0, 1
2, 1

Answer 1

Answer:

Step-by-step explanation:

As (1 – p) is root of the equation: x2 + px + (1 – p) = 0

(1 – p)2 + p(1 – p) + (1 – p) = 0

(1 – p)[1 – p + p + 1] = 0

(1 – p) = 0

p = 1

Therefore, given equation now becomes

x2 + x = 0

x(x + 1) = 0

x = 0, -1

The correct option is A.