if (1-p) is a root of the equation x2+px+1-p=0 then roots are
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1-p) is a root of the equation x2+px+1-p=0 then roots are
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We are given that one of the roots of the given equation x2+ px + (1 - p) = 0is (1-p). Let αbe the other root of the equation. Hence, one of the roots of the equation x2+ px + (1 - p) = 0 is -1. Hence, one of the roots of the equation x2+ px + (1 - p) = 0is 0.
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