Question

If (1-p) is a root of the quadratic equation x^2+px+(1-p)=0,then its roots are?​

Answer 1

Answer:

Substituting x=1−p, we get

(1−p)

2

+p(1−p)+(1−p)=0

(1−p)(1−p+p+1)=0

Hence, p=1

Thus, x=0 is root of the equation.

Now, the equation changes to

x

2

+x=0

x(x+1)=0

x=0 and x=−1