Question

if (1-p) is a zero of x^2+px+1-p then fond both the zeros​

Answer 1

Answer:

Substituting x=1−p, we get

(1−p)

2

+p(1−p)+(1−p)=0

(1−p)(1−p+p+1)=0

Hence, p=1

Thus, x=0 is root of the equation.

Now, the equation changes to

x

2

+x=0

x(x+1)=0

x=0 and x=−1