Question

If 1 side of a square is increased by 2 meters and the other size is reduced by 2 meters at rectangle is formed whose perimeter is 48 m . Find the side of the original square

Answer 1

Answer:

Let q be the side of the square.

Area of the square= x^2

Area of the rectangle

= length x breadth

= (q+3)(q-2)

Given, area if the rectangle is 4 m^2 more than  the area of the square.

(q+3)(q-2)= (q^2) + 4

(q^2) + 3q - 2q -6 = (q^2) + 4

(q^2) + q -6 = (q^2) + 4

q-6 = 4

q= 4+6

q = 10

I Hope this answer helps you ....