Question

if 1/sin^2theta- 1/cos^2theta - 1/tan^2 theta - 1/cot^2theta - 1/sec^2theta -1/cosec^2theta =-3 then find the value of theta.​

Answer 1

Answer:

0°

Step-by-step explanation:

break tan theta and cot theta into sin theta and cos theta . put sec theta =1/ cos theta and cosec theta = 1/ sin theta

simplify it as shown in photo.

now put sin^ 4 theta and cos^ 4 theta and 4 sin^2 theta cos^2 theta together as (cos^2 theta + sin ^ 2 theta )^2 .

furthermore put cos^2 theta - sin^ 2 theta as cos2 theta

you will get cos 2 theta as 1 therefore theta =0°