Question

If 1+sin2a=3sina.cosa,then show that tana=1 or 1/2

Answer 1

Answer:

Wrong question:

Right  Question: 1+sin²a = 3sina×cosa

Given that

1+Sin²a= 3Sina×Cosa

Cos²a+Sin²a+Sin²a = 3Sina× Cosa [ as we know that  1 = Sin²+Cos A]

Cos²a+2Sin²a= 3Sina Cosa  ....(1)

DIVIDE (1) By COS²a we get

1+2tan²a = 3tan a

1+2tan²a - 3tan a = 0

(2tan a-1) ( tan a-1) = 0

2tan a -1 = 0. tan a -1= 0

2tan a = 1. tan a =1

therefore tan a = 1 or 1/2