Question

if 1+sin²A = 3sinAcosA then prove that tanA = 1 or 1/2​

Answer 1

Answer:

check the photo I have sent all the steps

Answer 2

Step-by-step explanation:

Given that

1 + sin^2 A = 3sinAcosA

Dividing the equation by (cos^2 A)

sec^2 A + tan^2 A = 3tanA

1 + 2tan^2 A = 3tanA... (as, sec^2 A = tan^2 A + 1)

2tan^2 A - 3tanA + 1 = 0

(tanA - 1) (2tanA - 1) = 0

Therefore, tanA = 1, 1/2

Hence proved.