Math, asked by rupadajak, 4 months ago

If 1-Sin2A/Cos2A =tan theta what is the value of theta​

Answers

Answered by amitnrw
2

Given :   (1 - sin2a)/cos2a  = tanθ

To Find :  Value of θ

Solution:

(1 - sin2a)/cos2a  = tanθ

1 = sin²a + cos²a

cos2a = cos²a - sin²a

sin2a = 2sinacosa

=> ( sin²a + cos²a  - 2sinacosa)/( cos²a - sin²a)  =  tanθ

=> ( ±(cosa - sina))²/(cos + sina)(cosa - sina)  =  tanθ

=> ( ±(cosa - sina)) /(cos + sina) = tanθ

Dividing numerator & denominator by cosa in LHS

=> ± ( 1 - tana)/(1 + tana)  = tanθ

1 =  tan(π/4)

=> ±( tan(π/4) - tana)/(1 + tan(π/4).tana)  = tanθ

=> ±tan((π/4) - a)  =  tanθ

=> θ =  (π/4) - a  ,  a -  (π/4)

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Answered by darius60
4

Answer:

1-sin2A/cos2A gets cut

therefore tan theta=1

therefore, tan theta=45

value f tan=45

Step-by-step explanation:

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