Question

if 1-sin2A/cos2A=tan thita then the value of thita is​

Answer 1

Step-by-step explanation:

1-sin2A/cos2A=tan∅

(1-2sinAcosA)/cos²A-sin²A= tan∅

(cos²A+sin²A-2sinAcosA)/cos²A-sin²A= tan∅

(cosA-sinA)²/cos²A-sin²A= tan∅

(cosA-sinA)/(cosA+sinA)=tan∅