if 1-tan^2 thetha=2/3,find thetha
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1- tan^2θ =2/3
tan^2θ =1-2/3
tan ^2θ =(3-2)/3
tan^2θ =1/3
tan θ = root (1/3)
tan θ = 1/ root3
tan θ = tan 30
θ = 30 degrees
tan^2θ =1-2/3
tan ^2θ =(3-2)/3
tan^2θ =1/3
tan θ = root (1/3)
tan θ = 1/ root3
tan θ = tan 30
θ = 30 degrees
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