Math, asked by dhairyasheth07, 5 months ago

if 1 tap can fill a certain in 3 hrs and one pipe empty water in 5 hrs then what time will be taken if both of them are kept together .
use 1 hr of 3 and 5- little hint for you'll

Answers

Answered by Pranshav18
0

Answer:

7 ½ hours

Step-by-step explanation:

One tap can fill a cistern in = 3 hours

Waste pipe can empty a cistern in = 5 hours

∴ One tap 1 hour work = 1/3

Waste pipe 1 hour work = 1/5

∴ One tap and waste pipe together 1 hour work

= 1/3 – 1/5 = (5 – 3)/15

= 2/15

∴ Empty cistern will be full in 15/2 hours

= 7 ½ hours

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