Question

If 1, w and w^2 are the cube root of unity. Find the value of (2+2w^2+3w)^8.​

Answer 1

Answer:

1+3w+w2+(1+3−w2)4=1+3w+w2+(−w2+4)4=1+3w+w2+w8−16w6+96w4−256w2+256=w8−16w6+96w4−255w2+3w+257=w2−16+96w−255w2+3w+257=241−256w2+99w