Question

If 1,w,w^2 are cube riots then find value of 2^w^3.2^w^5.2^w is

Answer 1

Step-by-step explanation:

We have,

${2}^{ {w}^{3} } . {2}^{ {w}^{5} }. {2}^{w}$

$= {2}^{ {w}^{3} + {w}^{5} + w }$

$= {2}^{ {w}^{3} + {w}^{3}. {w}^{2} + w }$

$= {2}^{ 1 + {w}^{2} + w }$

$= {2}^{ 0} = 1$