if 1,w, w^2 are the cube roots of Unity then (3+5w+3w^2)^2 is a)6 b)8 c)12 d)4
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Answer:
Given,
1+3w+w
2
+(1+3−w
2
)
4
=1+3w+w
2
+(−w
2
+4)
4
=1+3w+w
2
+w
8
−16w
6
+96w
4
−256w
2
+256
=w
8
−16w
6
+96w
4
−255w
2
+3w+257
=w
2
−16+96w−255w
2
+3w+257
=241−256w
2
+99w
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