if 1,w, w^2 are the cube roots of Unity then (3+5w+3w^2)^2 is a)6 b)8 c)12 d)4
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Answer:1+3w+w2+(1+3-w2)4
Answer:1+3w+w2+(1+3-w2)41=3w +w2+(-w2+4)4
Answer:1+3w+w2+(1+3-w2)41=3w +w2+(-w2+4)4=1+3w+w2+w8+16w6+96w-256w2+256
= w8-16w6+96w -255w2+3w +257
=241-256w2+99w.
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