Question

If 1 w w2 are the cube roots of unity then prove the (3+3w+5w^2)^6-(2+6w+2w^2)^3=0.

Answer 1

Answer:

Step-by-step explanation:

Step-by-step explanation:

CSA = 32 m sq

= 2(l + b) h = 32

= (l + b) h = 16

TSA = 86 m sq

= 2(lb + bh + lh) = 86

= (lb + bh + lh) = 43

= lb + h(l+b) = 43

= lb + 16 = 43

lb = 43 - 16 = 27

lb = 27

Read more on Brainly.in - https://brainly.in/question/6825007#readmore