if 1,w,w² are threee cube root of unity , prove that :. (1 - w - w² )^6 =64
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Answer:
We know 1+w+w2=0
—》(1+w2−w)=−2w
—》(1−w2+w)=−2w2
—》(1+w2−w)(1−w2+w) =4w3=4×1=4
(Since w3=1 )
DONE.
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