If (1+x)^1+x2+2x=16,then x=
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Correct option is B)
Given22x−y=32⇒22x−y=25⇒2x−y=5−−−−(1)Again2x+y=16⇒2x+y=24⇒x+y=4−−−−(2)Adding(1)and(2)weget3x=9⇒x=3Substitutingx=3in(2)wegety=1.∴x2+y2=32+12=10(Ans)
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