If 1/x,1/y,1/z are A.P., show thatb
Yz, zx, xy are in A.P
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Step-by-step explanation:
for A.P we know (an+an+2)/2=an+1
so (1/x+1/z)/2=1/y solving this you will get 2xz=yx+yz
reaarange this xz=(yx+yz)/2 here is your answer
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