Question

if 1/x, 1/y , 1/z are in AP show that (y+z)/x, (x+z)/y, (x+y)/z

Answer 1

given: 1/x , 1/y and 1/z are in AP.
Now,

Multiplying each term of given AP by (x+y+z)
​therefore
x+y+z/x ,x+y+z/y , x+y+z/z are in AP
x+y+z/x −1 ,x+y+z/y −1, x+y+z/z -1
are in AP  [subtracting 1 from each term]
y+z/x, x+z/y, x+y/z  are in AP.

Answer 2

Step-by-step explanation:

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...thanking you

Mohit Sharma