if 1/x,1/y,1/z are in AP then find y
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y = 2xz/(x + z) if 1/x,1/y,1/z are in AP
Step-by-step explanation:
1/x , 1/y . 1/z are in AP
=> 1/y - 1/x = 1/z - 1/y
=> (x - y)/xy = (y - z)/yz
=> (x - y)/x = (y - z)/z
=> xz - yz = xy - xz
=> 2xz = xy + yz
=> 2xz = y(x + z)
=> y = 2xz/(x + z)
Learn more:
if a,8,b are in AP; a,4,b are in GP; a,x,b are in HP then x
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if abc are in AP and BCD are in HP then prove that ad is equal to BC
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